-x^2+60x-500=-500

Solution for -x^2+60x-500=-500 equation:

-x^2+60x-500=-500

We move all terms to the left:

-x^2+60x-500-(-500)=0

We add all the numbers together, and all the variables

-1x^2+60x=0

a = -1; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·(-1)·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*-1}=\frac{-120}{-2}
=+60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*-1}=\frac{0}{-2}
=0
$